sqlserver字符串拆分

有表tb, 如下:
id value

–方法0:动态SQL法

sqlserver字符串拆分(split)方法汇总

 转载

–方法0:动态SQL法 declare @s varchar(100),@sql varchar(1000)
set @s=’1,2,3,4,5,6,7,8,9,10′
set @sql=’select col=”’+ replace(@s,’,’,”’ union all select
”’)+””
PRINT @sql
sqlserver字符串拆分。exec (@sql)

 

if exists (select * from dbo.sysobjects where id =
object_id(N'[dbo].[f_splitSTR]’) and xtype in (N’FN’, N’IF’,
N’TF’))
drop function [dbo].[f_splitSTR]
GO
–方法1:循环截取法 CREATE FUNCTION f_splitSTR(
@s   varchar(8000),   –待分拆的字符串
@split varchar(10)     –数据分隔符
)RETURNS @re TABLE(col varchar(100))
AS
BEGIN
 DECLARE @splitlen int
 SET @splitlen=LEN(@split+’a’)-2
 WHILE CHARINDEX(@split,@s)>0
 BEGIN
  INSERT @re VALUES(LEFT(@s,CHARINDEX(@split,@s)-1))
  SET @s=STUFF(@s,1,CHARINDEX(@split,@s)+@splitlen,”)
 END
 INSERT @re VALUES(@s)
 RETURN
END
GO

 

if exists (select * from dbo.sysobjects where id =
object_id(N'[dbo].[f_splitSTR]’) and xtype in (N’FN’, N’IF’,
N’TF’))
drop function [dbo].[f_splitSTR]
GO
–方法2:使用临时分拆协理表法
CREATE FUNCTION f_splitSTR(
@s   varchar(8000),  –待分拆的字符串
@split varchar(10)     –数据分隔符
)RETURNS @re TABLE(col varchar(100))
AS
BEGIN
 –创立分拆处理的协助表(用户定义函数中不得不操作表变量)
 DECLARE @t TABLE(ID int IDENTITY,b bit)
 INSERT @t(b) SELECT TOP 8000 0 FROM syscolumns a,syscolumns b

 INSERT @re SELECT SUBSTRING(@s,ID,CHARINDEX(@split,@s+@split,ID)-ID)
 FROM @t
 WHERE ID<=LEN(@s+’a’)
  AND CHARINDEX(@split,@split+@s,ID)=ID
 RETURN
END
GO

 

if exists (select * from dbo.sysobjects where id =
object_id(N'[dbo].[f_splitSTR]’) and xtype in (N’FN’, N’IF’,
N’TF’))
drop function [dbo].[f_splitSTR]
GO
if exists (select * from dbo.sysobjects where id =
object_id(N'[dbo].[tb_splitSTR]’) and
objectproperty(id,N’IsUserTable’)=1)
drop table [dbo].[tb_splitSTR]
GO
–方法3:使用永久性分拆援救表法 –字符串分拆扶助表
SELECT TOP 8000 ID=IDENTITY(int,1,1) INTO dbo.tb_splitSTR
FROM syscolumns a,syscolumns b
GO
–字符串分拆处理函数
CREATE FUNCTION f_splitSTR(
@s     varchar(8000),  –待分拆的字符串
@split  varchar(10)     –数据分隔符
)RETURNS TABLE
AS
RETURN(
 SELECT col=CAST(SUBSTRING(@s,ID,CHARINDEX(@split,@s+@split,ID)-ID) as
varchar(100))
 FROM tb_splitSTR
 WHERE ID<=LEN(@s+’a’)
  AND CHARINDEX(@split,@split+@s,ID)=ID)
GO

 

–方法4:利用sql server2005的OUTER APPLY

CREATE FUNCTION [dbo].[ufn_SplitStringToTable]
(
  @str VARCHAR(MAX) ,
  @split VARCHAR(10)
)
RETURNS TABLE
    AS
RETURN
    ( SELECT    B.id
      FROM      ( SELECT    [value] = CONVERT(XML , ‘<v>’ +
REPLACE(@str , @split , ‘</v><v>’)
                            + ‘</v>’)
                ) A
      OUTER APPLY ( SELECT  id = N.v.value(‘.’ , ‘varchar(100)’)
                    FROM    A.[value].nodes(‘/v’) N ( v )
                  ) B
    )

 

备注表达:

办法4须要在sql server2005下才方可运作

Java、.net等开发工具具有split成效,近期在Sqlserver中碰着那么些须求。


declare @s varchar(100),@sql varchar(1000)
set @s='1,2,3,4,5,6,7,8,9,10'
set @sql='select col='''+ replace(@s,',',''' union all select ''')+''''
PRINT @sql
exec (@sql)

--方法1:循环截取法

if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[f_splitSTR]') and xtype in (N'FN', N'IF', N'TF'))
drop function [dbo].[f_splitSTR]
GO
CREATE FUNCTION f_splitSTR(
@s   varchar(8000),   --待分拆的字符串
@split varchar(10)     --数据分隔符
)RETURNS @re TABLE(col varchar(100))
AS
BEGIN
 DECLARE @splitlen int
 SET @splitlen=LEN(@split+'a')-2
 WHILE CHARINDEX(@split,@s)>0
 BEGIN
  INSERT @re VALUES(LEFT(@s,CHARINDEX(@split,@s)-1))
  SET @s=STUFF(@s,1,CHARINDEX(@split,@s)+@splitlen,'')
 END
 INSERT @re VALUES(@s)
 RETURN
END
GO

方法1:动态SQL法

1 aa,bb
2 aaa,bbb,ccc
欲按id,分拆value列, 分拆后结果如下:
id value

 –方法2:使用暂行分拆扶助表法

declare @string varchar(100),@sql varchar(1000)
set @string='1,2,3,4,5,6,7,8,9,10'
set @sql='select col='''+ replace(@string,',',''' union all select ''')+''''
PRINT @sql
exec (@sql)
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